@echo off
:: 普通的 for+findstr 语句会忽略分号开头的行
:: findstr /n .* 用delims=:后，会忽略行首所有的冒号
:: 还有!、、.等特殊符号需要处理
:: 以下代码可以准确提取这些敏感字符
:: 解决了 setlocal 最大递归层的问题(setlocal 两两嵌套处理超过15行内容时会带来此问题)
:: 能计算空行
:: code by jm 2006-12-12 thanks 3742668 CMD@XP
set num=0
for /f "delims=" %%i in ('findstr /n .* test.txt') do (
set /a num+=1
set "str=%%i"
setlocal enabledelayedexpansion
echo 第 !num! 行： !str:*:=!
endlocal
)
pause
goto :eof
@echo off
:: 超过15行内容时，会带来 setlocal 最大递归层的问题
:: code by 3742668 2006-12-11 CMD@XP
@echo off
setlocal enabledelayedexpansion
set num=
for /f "eol= delims=" %%i in ('findstr .* a.txt') do (
setlocal DISABLEDELAYEDEXPANSION
set "tmpstr=%%i"
setlocal enabledelayedexpansion
set /a num += 1
set "!num!=!tmpstr!"
)
for /l %%i in (1,1,%num%) do echo 第%%i行: !%%i!
pause
exit /b 0
@echo off
:: 不能正确提取带感叹号的内容
:: code by jm 2006-12-11 CMD@XP
set num=0
setlocal enabledelayedexpansion
for /f "delims=" %%i in ('findstr /n .* test.txt') do (
set /a num+=1
set "str=%%i"
echo 第 !num! 行： !str:*:=!
)
pause
goto :eof
@echo off
:: 结果要用引号括起来
:: code by jm 2006-12-11 CMD@XP
set num=0
::setlocal enabledelayedexpansion
for /f "delims=" %%i in ('findstr /n .* test.txt') do (
set /a num+=1
set "str=%%i"
call :display
)
pause
goto :eof
:display
echo 第 %num% 行： "%str:*:=%"
goto :eof
test.txt的内容
:abc
::xy

;;;ef
;:;
::;;


^
!
!
%
"
""
'
test
abc